35.356t-4.905t^2=0

Solution for 35.356t-4.905t^2=0 equation:

35.356t-4.905t^2=0

a = -4.905; b = 35.356; c = 0;
Δ = b2-4ac
Δ = 35.3562-4·(-4.905)·0
Δ = 1250.046736
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(35.356)-\sqrt{1250.046736}}{2*-4.905}=\frac{-35.356-\sqrt{1250.046736}}{-9.81}
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(35.356)+\sqrt{1250.046736}}{2*-4.905}=\frac{-35.356+\sqrt{1250.046736}}{-9.81}
$